2x-x^2-80=0

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Solution for 2x-x^2-80=0 equation:


Simplifying
2x + -1x2 + -80 = 0

Reorder the terms:
-80 + 2x + -1x2 = 0

Solving
-80 + 2x + -1x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
80 + -2x + x2 = 0

Move the constant term to the right:

Add '-80' to each side of the equation.
80 + -2x + -80 + x2 = 0 + -80

Reorder the terms:
80 + -80 + -2x + x2 = 0 + -80

Combine like terms: 80 + -80 = 0
0 + -2x + x2 = 0 + -80
-2x + x2 = 0 + -80

Combine like terms: 0 + -80 = -80
-2x + x2 = -80

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -80 + 1

Reorder the terms:
1 + -2x + x2 = -80 + 1

Combine like terms: -80 + 1 = -79
1 + -2x + x2 = -79

Factor a perfect square on the left side:
(x + -1)(x + -1) = -79

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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